What will be the output of the following C++ code?

#include<stdio.h>

int main()

{

 int i=12;

int j=sizeof(i++);

printf("%d %d",i,j);

return 0;

}

What is the name of the following operator?:

 Now consider a slightly modified version of the previous question. Is it possible that function foo is called? 

int x;
&x;
if (x != x) foo();

Predict the output of the following C program:

#include <stdio.h>

int main()

{

int a[] = {1, 2, 3, 4, 5, 6};

int *ptr = (int*)(a + 1);

printf("%d", *(ptr - 1));

return 0;

}

#include<stdio.h>

#include<stdarg.h>

int func(int count,...)

{

int val=0,i;

va_list p;

va_start(p,n,count);

for(int j=1;j<;j++)

   {

     i=va_arg(p,count);

     val+=i;

   }

va_end(p);

return val;

}

int main()

{

printf("%d",func(4,3,2,1));

return 0;

}

What will be the output of the following C++ code?

#include <iostream>

using namespace std;

int main()

{

int x = -1;

unsigned int y = 2;

if(x > y) 

{

cout << "x is greater";

}

else 

{

cout << "y is greater";

} 

}

#include <stdio.h>

#define SIZE(arr) sizeof(arr) / sizeof(*arr);

void fun(int* arr, int n)

{

int i;

*arr += *(arr + n - 1) += 10;

}

void printArr(int* arr, int n)

{

int i;

for(i = 0; i < n; ++i)

printf("%d ", arr[i]);

}

int main()

{

int arr[] = {10, 20, 30};

int size = SIZE(arr);

fun(arr, size);

printArr(arr, size);

return 0;

}

What will be the output of the following C++ code?

#include <iostream>
using namespace std;
class A{
public:
A(){
cout<<"Constructor called\n";
  }
~A(){
cout<<"Destructor called\n";
   }
};
int main(int argc, char const *argv[])
{
A *a = new A[5];
delete a;
return 0;
}

Consider the following C code:

#include <stdio.h> int * assignval (int *x, int val) { *x = val; return x; } int main() { int *x = malloc(sizeof(int)); if (NULL == x) return; x = assignval(x, 0); if(x) { x = (int*) malloc(sizeof (int)); if (NULL == x) return; x = assignval (x, 10); } printf("%dn", *x); free(x); }

The code suffers from which one of the following problems: