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Signals-and-systems Questions Set 62:

Quiz Mode

Find the even component of a continuous time signal x(t)=e^j8t

cos8t

jcos8t

sin8t

jsin8t

Solution:

Find the odd component of the discrete sequence x(n)={1,2,9}

{-4,4,4}

{0,0,0}

{-4,0,4↑}

{-4,0,0}

Solution:

The modulated signal y(t)=m(t)cos(4pit). Calculate the carrier frequency of the given signal

1hz

2hz

3hz

4hz

Solution:

The modulated signal y(t)=m(t)cos(400pit). Calculate the carrier frequency of the given signal

200hz

400hz

800hz

1600hz

Solution:

The impulse response of a system is h(t)=(t-2)u(t). For an input u(t-1), the output is

u(t)

u(t-1)

u(t-2)

u(t-2)(t-3)²/2

Solution:

The impulse response of a system is h(t)=t²u(t). For an input u(t-1), the output is

u(t-1)(t-1)²/2

u(t-1)(t-1)/2

u(t-1)(t-1)⁴/2

none

Solution:

A signal is sampled 2khz and is quantized using 8-bit uniform quantizer assuming SNR for a sinusoidal signal, the bit rate is

1kbps

16kbps

6kbps

10kbps

Solution:

Four messages are band limited to w,w,2w and 2w are to be multiplexed using time division multiplexing. The minimum bandwidth required for transmission is

Solution:

A band limited signal with a maximum frequency of 4khz is to be sampled. According to the sampling theorem, the sampling frequency which is not valid is

6khz

8khz

10khz

12khz

Solution:

Three analog signals,having bandwidths 600hz,600hz and 300hz are sampled at their respective Nyquist rates, encoded with 12 bit words and time division multiplexed. The bit rate for the multiplexed signal is

32.4kbps

30.4kbps

32kbps

30kbps

Signals-and-systems Questions Set 62:

Find the even component of a continuous time signal x(t)=e^j8t

Solution:

Find the odd component of the discrete sequence x(n)={1,2,9}

Solution:

The modulated signal y(t)=m(t)cos(4pit). Calculate the carrier frequency of the given signal

Solution:

The modulated signal y(t)=m(t)cos(400pit). Calculate the carrier frequency of the given signal

Solution:

The impulse response of a system is h(t)=(t-2)u(t). For an input u(t-1), the output is

Solution:

The impulse response of a system is h(t)=t²u(t). For an input u(t-1), the output is

Solution:

A signal is sampled 2khz and is quantized using 8-bit uniform quantizer assuming SNR for a sinusoidal signal, the bit rate is

Solution:

Four messages are band limited to w,w,2w and 2w are to be multiplexed using time division multiplexing. The minimum bandwidth required for transmission is

Solution:

A band limited signal with a maximum frequency of 4khz is to be sampled. According to the sampling theorem, the sampling frequency which is not valid is

Solution:

Three analog signals,having bandwidths 600hz,600hz and 300hz are sampled at their respective Nyquist rates, encoded with 12 bit words and time division multiplexed. The bit rate for the multiplexed signal is

Solution:

Related Question Sets:

Related Topics:

Signals-and-systems Questions Set 62:

Find the even component of a continuous time signal x(t)=ej8t

Solution:

Find the odd component of the discrete sequence x(n)={1,2,9}

Solution:

The modulated signal y(t)=m(t)cos(4pit). Calculate the carrier frequency of the given signal

Solution:

The modulated signal y(t)=m(t)cos(400pit). Calculate the carrier frequency of the given signal

Solution:

The impulse response of a system is h(t)=(t-2)u(t). For an input u(t-1), the output is

Solution:

The impulse response of a system is h(t)=t2u(t). For an input u(t-1), the output is

Solution:

A signal is sampled 2khz and is quantized using 8-bit uniform quantizer assuming SNR for a sinusoidal signal, the bit rate is

Solution:

Four messages are band limited to w,w,2w and 2w are to be multiplexed using time division multiplexing. The minimum bandwidth required for transmission is

Solution:

A band limited signal with a maximum frequency of 4khz is to be sampled. According to the sampling theorem, the sampling frequency which is not valid is

Solution:

Three analog signals,having bandwidths 600hz,600hz and 300hz are sampled at their respective Nyquist rates, encoded with 12 bit words and time division multiplexed. The bit rate for the multiplexed signal is

Solution:

Related Question Sets:

Related Topics:

Find the even component of a continuous time signal x(t)=e^j8t

The impulse response of a system is h(t)=t²u(t). For an input u(t-1), the output is